find the value of p(t) = (t-1) (t - 2) (t-3) at t= (-1)
Answers
Answered by
3
Solution :
given :
p(t) = (t-1) (t - 2) (t-3)
t = -1
To find :
The value
Solution :
p(t) = (-1 - 1) (-1 - 2) (-1 - 3)
= -2 x -3 x -4
= -2 x 12
= -24
=> The answer is -24
Extra information :
polynomial function : a polynomial function in variable x with degree n is defined as polynomial function
Ex.
p(x) = a_n x^n , a_n - 1 x^n - 1 ,a_n - 2 x^n - 2, a_n- 3 x^n-3 .............a_0
Answered by
0
Step-by-step explanation:
p(t) = (t-1) (t-2) (t-3)
if we put t = -1,
p(-1) = (-1 -1) (-1 -2) ( -1 -3)
= (-2) (-3) (-4)
= -24
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