Find the value of p, when px² + (√3 - √2x - 1 = 0 and x = 1 /3
Answers
Answered by
0
Answer:
Px(x-3) + 9 = 0
px2-3px+9=0
a=p , b=-3p , c=9
b2-4ac= (-3p)2-4(p)(9)
=9p2-36p
for having equal roots
b2-4ac = 9p2-36p = 0
9p2-36p = 0
9p(p-4) = 0
9p=0 (or) p-4=0
p=0(rejected) or p=4
Answered by
0
Answer:
will you get your correct answer
Attachments:
Similar questions