Question

find the value of p when the distance between the points a(3,p) and b(4,1) is √10​

Answer 1

Answer:

4

Step-by-step explanation:

Let A(3,a) and B(4,1) be the points of a line AB

Distance AB=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

⇒

10

=

(1−a)

2

+(4−3)

2

Squaring both sides, we get

⇒10=(1−a)

2

+(4−3)

2

⇒10=1+a

2

−2a+1=0

⇒a

2

−2a−8=0

⇒a

2

−4a+2a−8=0

⇒a(a−4)+2(a−4)=0

⇒(a−4)(a+2)=0

∴a=−2 or a=4