Question

Find the value of p when (x2+3x+p) is divisible by x-2.​

Answer 1

Question :

Find the value of p when (x2+3x+p) is divisible by x-2.

Solution :

x² + 3x + p is divisible by x-2.

So, x-2=0

==>x = 2

2 is the zero of the polynomial x² + 3x + p.

Substituting 2 in x place :

(2)² + 3(2) + p = 0

4 + 6 + p = 0

10 + p = 0

p = -10

Therefore, the value of p is -10 when x² + 3x + p is divisible by x-2.

Verification :

x² + 3x + p = 0

(2)² + 3(2) + (-10) = 0

4 + 6 - 10 = 0

0 = 0

Hence, verified !!

Hola !

Mark it as Brainliest if you found it helpful !!

✌️

Answer 2

Answer:

Maybe 20.......

Step-by-step explanation:

Hope it helps...........