Question

Find the value of p when (x2+3x+p) is divisible by x-2.​

Answer 1

Step-by-step explanation:

p(x)= x²+3x+p

g(x)= x-2

Equating g(x) to 0,

x-2=0

x=2

Putting p(x),

p(x)= x²+3x+p

p(2) = 4+6+p=0 (As p(x) is divisible by x-2)

==> p+10=0

==> p=-10

Answer 2

Answer:

The Answer is -10

This is Correct