Question

find the. value of p where p(y)=y square +1​

Answer 1

Answer:

p(y)=y^2+1

py=y^2+1

p=y^2-y+1 [on transposition]

Step-by-step explanation:

Answer 2

Answer:

p(0)=0²-0+1

p(0)=1

p(1)=1²-1+1

p(1)=1-0

p(1)=1

p(2)=2²-2+1

p(2)=4-1

p(2)=3

Step-by-step explanation:

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