Question

find the value of p which qudratic equation 4xsquare - ( p-2 ) 1 = 0 has equal roots​

Answer 1

Step-by-step explanation:

1. bsqure _4ac
2. Substitute the values
3. including a,bc
4. factorization
5. finished at all
6. there is no equal real roots.

Answer 2

Answer:

b²-4ac=0

(p-2)²-(4*4*1)=0

p²+4-4p-16=0

p²-4p-12=0

p²+2p-6p-12=0

p(p+2)-6(p+2)=0

(p+2)(p-6)=0

P= -2. or. P= 6.......

Thank you.

Step-by-step explanation: