find the value of p which the pair of linear equations (p-3)x+3y=p and px+py=12
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Step-by-step Given: SP║RQ, ∠R = 90° and ∠Q = 130°.
To find: The measure of ∠P.
Answer:
It is given that SP║RQ. So let us assume that PQ is the transversal.
Therefore, ∠P + ∠Q = 180° (Co - interior Angles are Supplementary)
∠P + 130° = 180°
∠P = 180° - 130°
∠P = 50°
Now let us assume that SR is the transversal.
Therefore, ∠S + ∠R = 180° (Co - interior Angles are Supplementary)
∠S + 90° = 180°
∠S = 180° - 90°
∠S = 90°explanation:
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