Math, asked by devika4983, 1 year ago

find the value of p which the pair of linear equations (p-3)x+3y=p and px+py=12
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Answers

Answered by sprao534
1
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Answered by Anonymous
0

Answer:

Step-by-step Given: SP║RQ, ∠R = 90° and ∠Q = 130°.

To find: The measure of ∠P.

Answer:

It is given that SP║RQ. So let us assume that PQ is the transversal.

Therefore, ∠P + ∠Q = 180° (Co - interior Angles are Supplementary)

∠P + 130° = 180°

∠P = 180° - 130°

∠P = 50°

Now let us assume that SR is the transversal.

Therefore, ∠S + ∠R = 180° (Co - interior Angles are Supplementary)

∠S + 90° = 180°

∠S = 180° - 90°

∠S = 90°explanation:

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