Question

find the value of P which the polynomial y^3+4y^2-py+8 is exactly divisible by y-2​

Answer 1

Answer:

we can find this by factor theorem,

Step-by-step explanation:

let,p(y)=y³+4y²-py+8.

g(y)=y-2

=>y-2=0

=>y=2

By putting the value of y we get

• (2)³+4(2)²-p(2)+8=0
• 8+16-2p+8=0
• 32-2p=0
• -2p=-32
• p=32÷2
• p=16