Question

find the value of p which will make the product of 2p-5 and p-4 equal in the value to p+8​

Answer 1

Answer:

(2p-5)(p-4) = p+8

2p^2 -8p -5p + 20= p+8

2p^2 -13p -p = 8-20

=2p^2- 14p +12=0

= 2p^2- 12 p - 2p +12=0

2p(p-6) -2(p-6)=0

=(2p-2)(p-6)=0

therefore p=6 & p=1

Step-by-step explanation:

Answer 2

Answer:

So, the required value of p is 3±✓3

Step-by-step explanation:

Given:

→(2p-5) × (p-4) = p+8

→2p²-5p-8p+20 = p+8

→2p²-13p+20 = p+8

→2p²-12p+12 = 0

→p²-6p+6 = 0

→p = {6±√(36-24)}/2

→p = (6±√12)/2

→p = (6±2√3)/2

→p = 3±✓3

→p = 3+√3 , 3-√3