Question

find the value of p x^2 -2x(1+3p)-7(3+2p)​

Answer 1

(p+1)x-(2p+3)y-1=0

x = 2

y = 3

(p+1)x-(2p+3)y-1=0

px + x -( 2py +3y)  -1 =0

px + x -2py - 3y -1= 0

putting the value of x and y 

p(2) + 2 - 2p(3) - 3(3) -1 = 0

2p  +2 -6p  -9  -1 = 0

-4p  - 8 = 0

-4p = 8

p = -2

Answer 2

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