Question

find the value of p(x)=√2x²+√2x+6 at x=√2​

Answer 1

$p(x)= \sqrt{2} x²+ \sqrt{2} x+6$

$at \: x= \sqrt{2} ,$

$p(x) = \sqrt{2} { (\sqrt{2}) }^{2} + \sqrt{2} ( \sqrt{2} ) + 6$

$\: \: \: \: \: \: \: \: \: \: = \sqrt{2}(2) + 2 + 6$

$\: \: \: \: \: \: \: \: \: \: = 2 \sqrt{2} + 8$

$\: \: \: \: \: \: \: \: \: \: = 2( \sqrt{2} + 4)$