Math, asked by rohit000011, 10 months ago

find the value of p(x)=3x³-4x²+7x-5 where x= 3 and x= -3​

Answers

Answered by Vishalk
11

If X = 3

= 3x³ -4x² + 7x -5

= 3(3)³ - 4(3)² + 7(3) - 5

= 81 - 36 + 21 - 5

= 102 - 41

= 61

If X = -3

= 3x³ -4x² + 7x -5

= 3(-3)³ - 4(-3)² + 7(-3) - 5

= - 81 - 36 - 21 - 5

= - 143

Answered by adiosdaxter
2

Answer: If x=(-3) then the answer is-143

If x=3 then the answer is 61

Step-by-step explanation:

If x=(-3) then,

P(-3)=3(-3)³-4(-3)²+7(-3)-5

P(-3)=3(-27)-4(9)+7(-3)-5

P(-3)=-81-36-21-5

P(-3)=-143.

If x=3 then,

P(3)=3(3)³-4(3)²+7(3)-5

P(3)=3x27-4x9+21-5

P(3)=81-36+21-5

P(3)=61.

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