find the value of p(x)=3x³-4x²+7x-5 where x= 3 and x= -3
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Answered by
11
If X = 3
= 3x³ -4x² + 7x -5
= 3(3)³ - 4(3)² + 7(3) - 5
= 81 - 36 + 21 - 5
= 102 - 41
= 61
If X = -3
= 3x³ -4x² + 7x -5
= 3(-3)³ - 4(-3)² + 7(-3) - 5
= - 81 - 36 - 21 - 5
= - 143
Answered by
2
Answer: If x=(-3) then the answer is-143
If x=3 then the answer is 61
Step-by-step explanation:
If x=(-3) then,
P(-3)=3(-3)³-4(-3)²+7(-3)-5
P(-3)=3(-27)-4(9)+7(-3)-5
P(-3)=-81-36-21-5
P(-3)=-143.
If x=3 then,
P(3)=3(3)³-4(3)²+7(3)-5
P(3)=3x27-4x9+21-5
P(3)=81-36+21-5
P(3)=61.
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