Math, asked by manpreetkaur3277, 9 months ago

find the value of p(x)=3ypower2-2y+8at y=-2​

Answers

Answered by rocky200216
1

24 .

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Answered by srikanthn711
12

Answer:

p(x) =  {3y}^{2}  - 2y + 8 \\  =  > p(-2) =   {3(-2)}^{2}  - 2(-2)  + 8 \\  =  >   \:  \:  \:  \:  \:  \: \:  \:  \:  \:  \:   =24

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