Question

find the value of p(x)
P(x) = x³-2x²​

Answer 1

Step-by-step explanation:

value of p(x)

p(1)= 1^3-2(1)^2

=1-2

=-1

p(2)=2^3-2(2)^2

= 8-8

=0

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value of x

x^3-2x^2=0

x^2(x-2)=0

x-2=0

x=2

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Answer 2

Answer:

$x = 2$

Step-by-step explanation:

$p(x) = {x}^{3} - {x}^{2} \\ \\ = > {x}^{3} - 2 {x}^{2} = 0 \\ \\ = > x( {x}^{2} - 2x) = 0 \\ \\ = > {x}^{2} - 2x = 0 \\ \\ = > {x}^{2} = 2x \\ \\ = > \frac{ {x}^{2} }{x} = 2 \\ \\ = > x = 2$

When we take X=2 then we will get the answer as 0

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