Question

Find the value of p (x)=x^3+2x^2-7x+3 at x=-3

Answer 1

P (x) = $x^{3} + 2x^{2} - 7x+3$
P(-3) = $(-3)^{3} + 2(-3)^{2} - 7(-3)+3$
P(-3) = (-27) + 18 +21 +3
P(-3) = 15

Hence the value is 15

Hope this answer is helpful for you

Please mark me brainliest

Answer 2

Hello , here is Ur answer ......

$let \: \: p(x) \: = \: {x}^{3} + 2 { x}^{2} - 7x + 3 \\ \\ = > p( - 3) = ( { - 3)}^{3} + 2( { - 3)}^{2} - 7( - 3) + 3 \\ \\ = > \:( - 27 )+ 2(9) + 21 + 3 \\ \\ = > ( - 21) + 18 + 21 + 3 \\ \\ = > 15\\ \\ so \:ans \: is \: 15$
Hope it's helps u☺☺