Question

Find the value of P(x)= x^3-6x^2+11x-6​

Answer 1

Answer:

Step-by-step explanation:

et p(x) = x3 + 6x2 +11x -6

given, x = 1/2

p(1/2) = (1/2)cube +6(1/2)sq +11 (1/2) -6

= 1/8 +6(1/4) +11/2 -6

= 1/8 + 3/2 +11/2 -6

=1/8 + 12/8 + 44/8 -48/8

= (1 +12+44-48)/8

= 9/8

Answer 2

Answer:

p(x)=x

3

−6x

2

+11x−6

p(1)=1−6+11−6=0

So (x−1) is a factor of p(x)

Dividing p(x) by (x−1) we get

q(x)=x

2

−5x+6

Factorising q(x)

q(x)=x

2

−3x−2x+6

q(x)=x(x−3)−2(x−3)

q(x)=(x−2)(x−3)

p(x)=(x−1)q(x)

p(x)=(x−1)(x−2)(x−3)

So the zeroes of the polynomial are x=1,2,3