Question

find the value of p(x)=x²-2x-3 ofx=4​

Answer 1

Answer:

p(x)=5

Step-by-step explanation:

p(x)=4^2-2×4-3

=16-8-3

=5

Answer 2

Given: $p(x)=x^2-2x-3$ and the value of$x$ is$4$.

We have to find the value of$p(x)=x^2-2x-3$.

As we can see that the value of$x$ is given that is$4$.

So, by putting this value of $x$in the equation$p(x)=x^2-2x-3$, we are solving the given problem.

We are solving in the following way:

We have,

$p(x)=x^2-2x-3$

Putting$x=4$ in$p(x)=x^2-2x-3$:

$=>p(4)=4^2-2\times4-3\\=>p(4)=16-8-3\\=>p(4)=16-11\\=>p(4)=5$

Hence, the value of$p(x)=x^2-2x-3$ will be$5$.