find the value of P(x) = x²-7x+
12 at x = 2, 1,3
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Answered by
0
p(2)=2^2-7*2+12
=4-14+12
=2
p(1)=1^1-7*1+12
=1-7+12
=-6+12
=6
p(3)=3^2-7*3+12
=9-21+12
=0
Answered by
0
Step-by-step explanation:
x^2-7x+12=(x-3)(x-4)
p(2)=(2-3)(2-4)=-1*-2=2
p(1)=(1-3)(1-4)=-2*-3=6
p(3)=(3-3)(3-4)=0
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