Question

find the value of P(x)=x⁴-2x²-x for P( 1 ) .​

Answer 1

Answer:

$p(x) = x {}^{4} - 2x {}^{2} - x \\ p(1) = 1 {}^{4} - 2 \times 1 {}^{2} - 1 \\ = 1 - 2 - 1 \\ = 1 - 3 \\ = - 2 \\ p(1) = - 2$

I hope it will help.

Answer 2

Answer:

Answer:

\begin{gathered}p(x) = x {}^{4} - 2x {}^{2} - x \\ p(1) = 1 {}^{4} - 2 \times 1 {}^{2} - 1 \\ = 1 - 2 - 1 \\ = 1 - 3 \\ = - 2 \\ p(1) = - 2 \end{gathered}

p(x)=x

4

−2x

2

−x

p(1)=1

4

−2×1

2

−1

=1−2−1

=1−3

=−2

p(1)=−2