Question

find the value of p(y)=2y^3-y^2-13y-6 for p(-3)​

Answer 1

Answer:

-12

Step-by-step explanation:

given p(y) = 2y³-y²-13y-6

therefore,

p(-3) = 2(-3)³ - (-3)² - 13 (-3) - 6

       = 2(-27) - (-9) +39-6

       = -54+9+33

       = -54+42

       = -12

Answer 2

Answer:

hi!!!!

here is your answer

Step-by-step explanation:

p(y) =2y^3-y^2-13y-6

p(-3) = 2(-3)^3-(-3)^2-13(-3)-6

p(-3) = 2(-27)-9+39-6

p(-3) =-54-9+39-6

p(-3) =63

hope this help you

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