Math, asked by vchore575, 3 days ago

find the value of p(y)=2y3-2y+7

Answers

Answered by asfandyarchandiosaha
0

Answer:

y =- 2

p(y)=2y^3-2y+v7 p(-2)=(2 x -2 x -2 x -2 )-( 2 x -2) + √7

p(-2) =- 16+4+√7 p(-2) =- 12+√7

Similar questions