find the value of p(y)=3y^3-4y+√11 at y=2
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Answer:
16+√11
Step-by-step explanation:
p(y) = 3y³ - 4y + √11
at y=2
3(2)³ - 4(2) + √11
3(8) - 8 + √11
24 - 8 + √11
16+√11
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