Question

find the value of p(y)= 3y^3 -4y+root 11 at y=2

Answer 1

Step-by-step explanation:

p(y) = 3(2)^3-4(2)+√11

= 24-8+√11

=16+√11

Answer 2

p (y) = 3y³-4y+√11

p (2)=3 (2)³-4(2)+√11

=3×8-8+√11

=24-8+√11

p (2)=16√11