Question

find the value of p(y)=y×y-y+1 if y=2​

Answer 1

Step-by-step explanation:

p(2)=4-2+1

p(2)=3

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Answer 2

Answer:

p(y)=y*y-y+1

p(2)=2*2-2+1

p(2)=4-2+1

2 is not equal to 3