Find the value of p2+3q2 when p=-1/2 and q= -2.
Answers
Answered by
2
Answer:
Answer
Given:(p
2
+q
2
+r
2
)(pq+qr)
Substituting p=2,q=−3 in the above equation, we get
=(2
2
+(−3)
2
+r
2
)(2×−3+(−3)r)
=(4+9+r
2
)(−6−3r)
=−(13+r
2
)(3r+6)
=−(39r+78+3r
3
+6r
2
)
=−(3r
3
+6r
2
+39r+78)
Answered by
5
Answer:
= p²+3q²
= (-1/2)²+3(-2)²
= -1/4+(3×-2×-2)
= -1/4+12
= 47/4
_____________.
Similar questions