Question

Find the value of p3-q3,if p-q=5/7 and pq=7/3

Answer 1

Answer:

$p^3-q^3=\frac{1840}{343}$

Step-by-step explanation:

$p-q=\frac{5}{7}\\\\p\cdot q =\frac{7}{3}\\\\Now, (p-q)^3=p^3-q^3-3\cdot p\cdot q\cdot (p-q)\\\\(\frac{5}{7})^3=p^3-q^3-3\times \frac{7}{3}\cdot (\frac{5}{7})\\\\\frac{125}{343}=p^3-q^3-7\times \frac{5}{7}\\\\p^3-q^3=\frac{125}{343}+5\\\\p^3-q^3=\frac{1840}{343}$

Answer 2

Answer:

Step-by-step explanation:

refer to the picture

hope it helps