Question

find the value of p³-q³ , if p-q= 5/7 and pq= 7/3.
I need answer ASAP.

Answer 1

$\huge\mathfrak{Answer}$

$\sf p-q=\frac{5}{7}$

$\sf pq =\frac{7}{3}$

$\sf (p-q){}^{3}=p{}^{3}-q{}^{3}-3pq(p-q)$

$\implies\sf \frac({5}{7}){}^{3}=p{}^{3}-q{}^{3}-3×\frac{7}{3}(\frac{5}{7})$

$\implies\sf \frac{125}{343}=p{}^{3}-q{}^{3}-7×\frac{5}{7}$

$\implies\sf \frac{125}{343}=p{}^{3}-q{}^{3}-5$

$\implies\sf \frac{125}{343}+5=p{}^{3}-q{}^{3}$

$\implies\sf \frac{125+1715}{343}=p{}^{3}-q{}^{3}$

$\implies\sf \frac{1840}{343} =p{}^{3}-q{}^{3}$

$\sf 5.364=p{}^{3}-q{}^{3}$

Answer 2

Answer:

plzz give me brainliest ans and plzzzz follow me