Question

Find the value of p3- q3, if p-q = -7 and pq= -10

Answer 1

Answer:

Given

p³-q³ where p-q=-7 and pq =-10

now

p³-q³=(p-q) (p²+q²+pq)

substitute value

(-7 ) (p²+q²-10)

where p,q

Answer 2

Step-by-step explanation:

p³-q³ = (p-q)(p²+q²+pq)

we have p-q = -7 and pq =-10

we have to find p² +q² first

so ,

(p-q)² = p²+q²-2pq

(-7)² = p² +q² -2(-10)

49 = p²+q²-(-20)

49 = p²+q²+20

49 - 20 =p²+q²

29 = p²+q²

Now we get p²+q²=29

put the values

p³ -q³ = (p-q) (p²+q²+pq )

= (-7) (29 +(-10))

= -7 × (29 -10 )

= -7 × 19

= -133

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