Question

Find the value of p³+ q³- r³-3pqr if p=4, q=3 and r=2

Answer 1

Answer:

${p}^{3} + {q}^{3} - {r}^{3} - 3pqr$

$= {4 }^{3} + {3}^{3} - {2}^{3} - 3 \times 4 \times 3 \times 2 \\ = 64 + 27- 8 - 72 \\ = 91 - 80\\ = 11 \: {answer}$