Question

find the value of polynomial 12x^2-7x+1,where x=1÷4

Answer 1

Heya !!!



X = 1/4




P(X) =>12X² - 7X +1




P(1/4) = 12 × ( 1/4)² - 7 × 1/4 + 1





=> 12 × 1/16 - 7/4 + 1





=> 3/4 - 7/4 + 1




=> 3 - 7 + 4 / 4




=> 7-7/4



=> 0/4




=> 0




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Answer 2

Given,

12x² - 7x + 1

x = 1/4

To find,

The value of the given polynomial.

Solution,

If x is 1/4 then the value of polynomial 12x² - 7x + 1 is 0.

We can easily solve this problem by following the given steps.

Now,

We have the value of x for the polynomial 12x² - 7x + 1.

Putting the value of x in 12x² - 7x + 1,

12x² - 7x + 1

12 × (1/4)² - 7 × 1/4 + 1

12/16 - 7/4 + 1

3/4 - 7/4 + 1 (Converting the fraction 12/16 into the simplest form)

Taking the Lowest Common Factor (L.C.M.) of 4,4, and 1 and adding these three numbers, we get

3-7+4/4

7-7/4

0/4

0

Hence, its value will be zero.