Find the value of polynomial 2y2-3y-4at y=5
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Answer:
2y²-3y-4=0 it's an quadratic polynomial .
When y= 5 .Then the value of the quadratic polynomial is as follows ...
p(y)=2y²-3y-4
p(5)= 2(5)²-3(5)-5
'"= 2×25-15-4
=50-15-4
=35-4
=31
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