Question

Find the value of polynomial 5x-4x2 +3 at i) x=0 ii) x=2​

Answer 1

$\huge\mathcal\colorbox{gold}{{\color{black}{AɴSᴡEʀ~~~↓}}}$

$\small{ }$

$\large\bold\color{navy}{To~find~:}$

The value of polynomial when :

i) x = 0

$\large\mathtt{p(0)=5(0)-4(0)^{2}+3}$

$\large\mathtt{~~~~~~~~~={\underline{\underline{3}}}}$

ii) x = 2

$\large\mathtt{p(2)=5(2)-4(2)^{2}+3}$

$\large\mathtt{~~~~~~~~~=10-4(4)+3}$

$\large\mathtt{~~~~~~~~~=10-16+3}$

$\large\mathtt{~~~~~~~~~=(-6)+3}$

$\large\mathtt{~~~~~~~~~={\underline{\underline{(-3)}}}}$

$\small{ }$

$\large\therefore\bold\color{navy}{Required~answer~:}$

When,

i) x = 0, the value of polynomial is 3

ii) x = 2, the value of polynomial is -3

$\small{ }$

$\huge\bold\color{gold}{Hope~it~helps..!!}$

Answer 2

) x = 0

Sol : Let p(x) = 4x2

– 5x + 3

If x = 0, then

p(0) = 4(0)2

– 5(0) + 3

= 0 – 0 + 3

= 3

ii) x = 2

Sol : Let p(x) =4x2

– 5x + 3

If x = 2, then

p(2) = 4(2)2

– 5(2) + 3

= 4(4) – 5(2) + 3

= 16 – 10 + 3

= 19 – 10

= 9