Question

find the value of polynomial 6x^2 - 4x +√3 at x=√3​

Answer 1

Answer:

Substituting value of x = √3 in given Equation.

$\therefore \: 6 \times \sqrt{3} {}^{2} - 4 \sqrt{3} + \sqrt{3}$

$6 \times 3 - 4 \sqrt{3} + \sqrt{3}$

$\therefore \: 18 - 4 \sqrt{3} + \sqrt{3}$

$\therefore \green{18 - 3 \sqrt{3}}$