find the value of polynomial 7+5x-4x^2, when x=0
Answers
Answered by
1
answer:
7
Step-by-step explanation:
7 + 5x -4x^2
where x = 0
So,
7 + 5*0- 4*0^2
= 7 + 0 - 0^2
= 7 + 0 - 0
= 7
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Answered by
0
Answer:
putting x=0
7+5(0)-4(0)²
7+0-0
=7
hope it helps
please mark me brainliest
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