Math, asked by shivamjaiswal11, 1 year ago

find the value of polynomial 7y-8y^2+20 at y=1 and y=2​

Answers

Answered by 2Ritz6
2

Step-by-step explanation:

7y - 8y^2 + 20

at y = 1

so , 7*1 - 8*1^2 + 20

=> 7 - 8 + 20

=> -1+20

=> 19

at y = 2

7*2 - 8* 2^2 + 20

=> 14-32+20

=> 6+32

=> 40

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Answered by dhakkchamp
1

Answer:

Hope it helps........

Thanks

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