Math, asked by mukesh1980, 9 months ago

Find the value of polynomial 8x3-6x2+2 at x=1.

Answers

Answered by tannurana59
82

Answer:

x+1 = 0

x = -1

8(-1)*3-6-(-1)*2+2

= -8-6+2

= -14+2

= -12

Step-by-step explanation:

~follow me please and Mark as brainliest I need it......

Answered by nafibarli789
9

The correct question is,

Find the value of polynomial 8x³ - 6x² + 2 at x = 1

Answer:

The value of polynomial 8x³ - 6x² + 2 at x = 1 is equal to 4.

Step-by-step explanation:

  • Polynomials exist in algebraic expressions that consist of variables and coefficients. Variables are even occasionally called indeterminates.
  • A polynomial exists as a category of algebraic expression in which the exponents of all variables should be a whole number.

It is provided that,

→ p(x) = 8x³ - 6x² + 2

putting x = 1 we get,

→ p(1) = 8(1)³ - 6(1)² + 2

→ p(1) = 8 × 1 - 6 × 1 + 2

→ p(1) = 8 - 6 + 2

Then,

→ p(1) = 10 - 6

We get,

→ p(1) = 4.

Hence, The value of polynomial 8x³ - 6x² + 2 at x = 1 is equal to 4.

#SPJ2

Similar questions