Question

find the value of polynomial f(y)=6y-3y+3 at y=0.


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Answer 1

Answer:

-3

Step-by-step explanation:

f (y)=6y-3y+3 y=0

=6×0-3×0+3

=0-0+3

=0-3

=-3

Answer 2

Answer:

Find the value of the polynomial

f(y) = 6y – 3y2 + 3 at

(i) y = 1

(ii) y = -1

(iii) y = 0

Step-by-step explanation:

(i) At y = 1,

f(1) = 6(1) – 3(1)2 + 3 = 6 – 3 + 3 = 6

(ii) At y = -1,

f(-1) = 6(-1) – 3(-1)2 + 3 = -6 – 3 + 3 = -6

(iii) At y = 0,

f(0) = 6(0) – 3(0)2 + 3 = 0 – 0 + 3 = 3

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