Question

find the value of polynomial f(y)=6y_3y+3at​

Answer 1

(i) At y = 1, f(1) = 6(1) – 3(1)2 + 3 = 6 – 3 + 3 = 6 (ii) At y = -1, f(-1) = 6(-1) – 3(-1)2 + 3 = -6 – 3 + 3 = -6 (iii) At y = 0, f(0) = 6(0) – 3(0)2 + 3 = 0 – 0 + 3 = 3

Answer 2

Answer:

[29/12, 10:57 p.m.] ya