find the value of polynomial p(x)=8x³-6x²-4x+3, when (1)=x=root 2
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Answered by
11
we know that
x=root 2
now putting the value of x in the polynomial PX
8*(root2)^3-6*(root2)^2-4*root2+3
8*root8-12-4root2+3
8root8-9-4root2 answer
note-we can use root sign..
answer.
x=root 2
now putting the value of x in the polynomial PX
8*(root2)^3-6*(root2)^2-4*root2+3
8*root8-12-4root2+3
8root8-9-4root2 answer
note-we can use root sign..
answer.
Answered by
1
Answer:
12√2-9
Step-by-step explanation:
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