Question

Find the value of polynomial x^2-3x+6 at a)x=√2 b) x=3

Answer 1

Answer:

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Step-by-step explanation:

Here is your answer

Gracías

Answer 2

${ \underline{ \sf{ \large{Solution}}}}$

(i)x = $\sqrt{2}$

$\longmapsto\sf{Putting \: values,}$

$\longmapsto \sf{x {}^{2} - 3x + 6 }$

$\longmapsto \sf{ \sqrt{2} {}^{2} - 3( \sqrt{2}) + 6 }$

$\longmapsto \sf{2 - 3 \sqrt{2} + 6 }$

$\longmapsto \sf\green{ \boxed{{\frak{{ = 8 - 3 \sqrt{2} }}}}}$

$\qquad { \underline{ \rule{666pt}{7.5pt}}}$

(ii)x = 3

$\longmapsto\sf{Putting \: values,}$

$\longmapsto \sf{x {}^{2} - 3x + 6 }$

$\longmapsto \sf{ 3 {}^{2} - 3( 3) + 6 }$

$\longmapsto \sf{ 9 -9 + 6 }$

$\longmapsto \sf\green{ \boxed{{\frak{{ = 6 }}}}}$

$\qquad { \underline{ \rule{666pt}{7.5pt}}}$