Question

Find the value of polynomial x2-3x+6 at x=root 2

Answer 1

Answer:

$x {}^{2} - 3x + 6 = 0 \\ at \: x = \sqrt{2} \\ put \: the \: value \: of \: x \: in \: above \: equation \\ ( \sqrt{2) {}^{2} } - 3 \sqrt{2} + 6 = 0 \\ 2 - 3 \sqrt{2} + 6 = 0 \\ 8 - 3 \sqrt{2} = answer$

I hope this is your answer

Answer 2

${ \underline{ \sf{ \large{Solution}}}}$

(i)x = $\sqrt{2}$

$\longmapsto\sf{Putting \: values,}$

$\longmapsto \sf{x {}^{2} - 3x + 6 }$

$\longmapsto \sf{ \sqrt{2} {}^{2} - 3( \sqrt{2}) + 6 }$

$\longmapsto \sf{2 - 3 \sqrt{2} + 6 }$

$\longmapsto \sf\green{ \boxed{{\frak{{ = 8 - 3 \sqrt{2} }}}}}$

$\qquad { \underline{ \rule{666pt}{7.5pt}}}$