Question

Find the value of polynomial y ²-3y + 1 if y=1​

Answer 1

Let f(y) = y^2 -3y + 1

Thus, f(y) at y = 1 is:

f(1) = (1)^2 - 3(1) + 1

= 1 - 3 + 1

= 2 - 3

= -1

Hence, the value of polynomial y ²-3y + 1 at y=1 is -1.

Answer 2

Answer:

The value of the polynomial at $y=1$ is -1.

Step-by-step explanation:

In context to the question asked,

We have to find the value of the polynomial at $y = 1$ or P ( 1 )

As per data given in the question,

The given polynomial,

$P ( y) = y^2-3y+1$

Now, by plugging the value of y as 1:

=> $P ( y) = y^2-3y+1$

=> $P ( 1) = (1)^2-3(1)+1$

Simplifying it further, we get

=> 1 - 3 + 1

=> -1

Hence, the value of polynomial at $y = 1$ is -1.