find the value of polynomial y²-3√2y+1 when y=3√2
Answers
Answered by
1
Answer:
1
Step-by-step explanation:
Given: y=3√2
To find: y²-3√2y+1
y²-3√2y+1
=(3√2)²-3√2(3√2)+1
=(9×2)-(9x2)+1
=0+1
=1
Answered by
1
Answer:
p(y)=y²-3√2y+1
g(y)=3√2
p(3√2)=3√2²-3√2(3√2)+1
3×3.(2)-3√2²+1
18-18+1
=1
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