Math, asked by Dhanesh3404, 1 year ago

Find the value of polynomial12x^2-7x+1 when x=1/4

Answers

Answered by itsmrkhan07
1

12x^2-7x+1    [substituting x=1/4 in the equation]

12(1/4)^2-7(1/4)+1

12/16-7/4+1

(3/4-7/4)+1

(-4/4)+1

-1+1

0


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