Question

Find the value of polynomial12x^2-7x+1,where if x=1÷2

Answer 1

p(x) = 2x^2 - 7x + 1

p(1/2) = 2(1/2)^2 - 7(1/2) + 1

=> 1/2 - 7/2 + 1

=> (1 - 7 + 2)/2

=> -2

Answer 2

Answer:

1/2

Step-by-step explanation:

12x^2-7x+1=?  x=1÷2

• 12x^2-7x+1=12*1/4-7*1/2+1=3-3 1/2+1= 1/2