Find the value of polynomials 6x-7x²+3 at X=2.
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Answered by
3
Answer:
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Answered by
3
Answer:
6x
2
−3−7x=6x
2
−7x−3=0
⇒6x
2
+2x−9x−3=0
⇒2x(3x+1)−3(3x+1)=0
⇒(2x−3)(3x+1)=0
Zeros =
2
3
,
3
−1
α+β=
a
−b
⇒
2
3
−
3
1
=
6
7
=
6
(−7)
=
a
−b
αβ=
a
c
⇒(
2
3
)(
3
−1
)=
2
−1
=
6
−3
=
a
c
Step-by-step explanation:
hope it help
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