Question

Find the value of positive integer n for which n^2 + 19n+ 48 is a perfect square.




jisko aaata ho wahi kar na​

Answer 1

Hey

Here is your answer,

n^2 + 19n + 48 = 0

n^2 + 3n + 16n + 48 = 0

n ( n+3) + 16 ( n+3) = 0

(n+3) (n+16) = 0

n+3=0

n=-3

n+16=0

n=-16