Question

Find the value of px2 - qy2 at x = 1 and y = (-1).​

Answer 1

Answer:

Answer

Given line is px

2

−qy

2

=0

General equation is ax

2

+by

2

+h=0

Comparing above equation with (i), we get

a=p,b=−q,h=0

Lines are real and distinct if h

2

−ab>0

⇒0+pq>0

⟹pq>0

Step-by-step explanation:

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Answer 2

Answer:

$p - q$

Step-by-step explanation:

$x=1\\y =(-1)$

$px^2 - qy^2$

$p(1)^2 - q(-1)^2$

$p - q$

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