Question

find the value of pythagoras theorem​

Answer 1

$6\sqrt{3}$Pythagoras theorem ==> a^2 + b^2 = h^2

In 1st triangle ABC

17^2 - 8^2 = a^2

289 - 64 = a^2

225 = a^2

a = $\sqrt{225}$ = 15 units

In 2nd triangle ACD

15^2 - 9^2 = y^2

225 - 81 = y^2

144 = y^2

y = $\sqrt{144}$ = 12 units

In 3rd triangle DCE

12^2 - 6^2 = x^2

144 - 36 = x^2

108 = x^2

x = $\sqrt{108}$ = $6\sqrt{3}$ units

Ans:- ∴ x = $6\sqrt{3}$ units

Refer to the document below for the markings of the triangle. Plz forgive if unclear

38967b232b1e16826263ad77cbc2ef2c.docx